According to Barkhausen criterion, a feedback type oscillator, having Aβ as loop gain, works if Aβ is made slightly greater than unity. As discussed in previous lectures, all practical oscillations involve:
- An active device to supply loop gain or negative resistance.
- A frequency selective network to determine the frequency of oscillation.
- Some type of non-linearity to limit amplitude of oscillations.
Harmonic Oscillator:
One feedback type harmonic oscillator circuit is shown in fig. 1.
Fig. 1 Fig. 2The dc equivalent circuit is shown in fig. 2. The dc operating point is set by selecting VCC, RB and RE. The ac equivalent circuit is also shown in fig. 3.Fig. 3The transformer provides 180° phase shift to ensure positive feedback so that at the desired frequency of oscillation, the total phase shift from vin to vx is made equal to 0° and magnitudes are made equal by properly selecting the turns ratio. RE also controls and stabilizes the gain through negative feedback. C2 and the transformers equivalent inductance make up a resonant circuit that determines the frequency of oscillation.C1 is used to block dc (Otherwise the base would be directly tied to VCC) through the low dc resistance of transformer primary. C1 has negligible reactance at the frequency of oscillation, therefore it is not apart of the frequency-determining network, the same applies to C2.In this circuit, there is an active device suitably biased to provide necessary gain. Since the active device produces loop phase shift 180º (from base to collector), a transformer in the feedback loop provides an additional 180º to yield to a loop phase shift of 0º. The feedback factor is equivalent to the transformer's turns ratio. There is also a turned circuit, to determine the frequency of oscillation.The load is in parallel with C2 and the transformer. If the load is resistive, which is usually the case, the Q of the tuned circuit and the loop gain are both affected, this must be taken into account when determining the minimum gain required for oscillation. If the load has a capacitive component, then the value of C2 should be reduced accordingly.
No comments:
Post a Comment