The Colpitts Oscillator:
Wein bridge oscillator is not suited to high frequencies (above 1MHz). The main problem is the phase shift through the amplifier.The alternative is an LC oscillator, a circuit that can be used for frequencies between 1MHz and 500MHz. The frequency range is beyond the frequency limit of most OPAMPs. With an amplifier and LC tank circuit, we can feedback a signal with the right amplitude and phase is feedback to sustain oscillations. Fig. 3, shows the circuit of colpitts oscillator.
Fig. 3 Fig. 4The voltage divider bias sets up a quiescent operating point. The circuit then has a low frequency voltage gain of rc / r'e where rc is the ac resistance seen by the selector. Because of the base and collector lag networks, the high frequency voltage gain is less then rc / r'e.Fig. 4, shows a simplified ac equivalent circuit. The circulating or loop current in the tank flows through C1 in series with C2. The voltage output equals the voltage across C1. The feedback voltage vfappears across C2. This feedback voltage drives the base and sustains the oscillations developed across the tank circuit provided there is enough voltage gain at the oscillation frequency. Since the emitter is at ac ground the circuit is a CE connection.Most LC oscillators use tank circuit with a Q greater than 10. The Q of the feedback circuit is given byBecause of this, the approximate resonant frequency isThis is accurate and better than 1% when Q is greater than 1%. The capacitance C is the equivalent capacitance the circulation current passes through. In the Colpitts tank the circulating current flows through C1 in series with C2.Therefore C = C1 C2 / (C1 +C2)The required starting condition for any oscillator is A β > 1 at the resonant frequency or A > 1/ β. The voltage gain A in the expression is the gain at the oscillation frequency. The feedback gain β is given byβ = vf / vout≈ XC1 / XC2Because same current flow through C1 and C2, thereforeβ = C1/ C2; A > 1/ v; A> C1 / C2This is a crude approximation because it ignores the impedance looking into the base. An exact analysis would take the base impedance into account because it is in parallel with C2 .With small β, the value of A is only slightly larger than 1/β. and the operation is approximately close A. When the power is switched on, the oscillations build up, and the signal swings over more and more of ac load line. With this increased signal swing, the operation changes from small signal to large signal. As this happen, the voltage gain decreases slightly. With light feedback the value of Aβ can decreases to 1 without excessive clapping.With heavy feedback, the large feedback signal drives the base into saturation and cut off. This charges capacitor C3 producing negative dc clamping at the base and changing the operation from class A to class C. The negative damping automatically adjusts the value of Aβ to 1.
Example - 1
Design a Colpitts oscillator that will oscillate at 100 kHz.Solution:Let us choose R1 = Rf = 5 kΩ and C = 0.001 µF. From the frequency expression,The quality factor (Q) of the LC circuit is given by:
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